chore: import original project baseline
Import the pre-repair source tree as the history baseline. Runtime data (data/), virtualenvs, bytecode caches and logs are gitignored so local secrets and user state stay out of the repo.
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# -*- coding: utf-8 -*-
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"""公式渲染验收消息注入:新建「公式渲染验收」会话,写入用户原始样本 + 正/负例
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运行: PYTHONIOENCODING=utf-8 python tests/inject_math_demo.py
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"""
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import os
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import sys
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sys.path.insert(0, os.path.join(os.path.dirname(__file__), ".."))
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from core.db_manager import DBManager # noqa: E402
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USER_MSG = """帮我看看这个推导,公式渲染对不对?
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上面是推导结果:
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[
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P_4=\\operatorname{BRF}(M_4,M_5)
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]
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[
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P_3=\\operatorname{BRF}(S_3,P_4)
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]
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其中:
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[
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\\operatorname{BRF}(L,H)
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L+
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\\Gamma(L,\\operatorname{Up}(H))
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\\odot
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\\Phi(\\operatorname{Up}(H))
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]
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"""
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ASSISTANT_MSG = r"""## 公式渲染验收
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### 1) 你原始样本(单括号块,应渲染为独立居中公式)
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上面是推导结果:
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[
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P_4=\operatorname{BRF}(M_4,M_5)
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]
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[
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P_3=\operatorname{BRF}(S_3,P_4)
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]
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其中:
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[
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\operatorname{BRF}(L,H)
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L+
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\Gamma(L,\operatorname{Up}(H))
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\odot
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\Phi(\operatorname{Up}(H))
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]
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### 2) 标准定界符
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行内混合:能量公式 $E=mc^2$ 出现在句子中间;再来一个 $x_i^2 + y_j^2 = z_{ij}^2$。
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行内括号形式:\(\alpha + \beta = \gamma\)
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双美元块:
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$$
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\int_{-\infty}^{\infty} e^{-x^2}\,dx = \sqrt{\pi}
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$$
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方括号块:
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\[
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\sum_{n=1}^{\infty} \frac{1}{n^2} = \frac{\pi^2}{6}
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\]
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带矩阵与希腊字母:
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[
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\begin{pmatrix} a & b \\ c & d \end{pmatrix}
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\begin{pmatrix} x \\ y \end{pmatrix}
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=
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\begin{pmatrix} ax+by \\ cx+dy \end{pmatrix}
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]
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### 3) 反例(不应渲染成公式)
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- 编号引用:见[1]和[2]的说明。
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- 链接:[KaTeX 官网](https://katex.org)
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- 列表内容:[a, b] 只是一个数组。
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- 货币:价格 $1,000 and $2,000 之间。
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- 代码块:
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```python
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price = "$5"
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pattern = r"$x + y$"
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arr[0] = 1
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```
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- 行内代码:使用 `$z$` 表示变量。
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### 4) 复杂嵌套(流式增量渲染路径同样适用)
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$$
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f(x) = \sum_{k=0}^{n} \binom{n}{k} x^k (1-x)^{n-k}
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$$
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"""
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def main():
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db = DBManager()
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sess = db.create_session("公式渲染验收")
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sid = sess["id"]
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parent = sess.get("current_leaf_msg_id")
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m1 = db.add_message(sid, "user", USER_MSG, parent_id=parent)
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db.add_message(sid, "assistant", ASSISTANT_MSG, parent_id=m1["id"])
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db.mark_session_has_messages(sid)
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print(f"已注入会话: {sid}")
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print(f"标题: 公式渲染验收")
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print(f"用户消息 {len(USER_MSG)}c / 助手消息 {len(ASSISTANT_MSG)}c")
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return 0
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if __name__ == "__main__":
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sys.exit(main())
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